3.1025 \(\int (a+b x)^2 (A+B x) (d+e x) \, dx\)

Optimal. Leaf size=75 \[ \frac{(a+b x)^4 (-2 a B e+A b e+b B d)}{4 b^3}+\frac{(a+b x)^3 (A b-a B) (b d-a e)}{3 b^3}+\frac{B e (a+b x)^5}{5 b^3} \]

[Out]

((A*b - a*B)*(b*d - a*e)*(a + b*x)^3)/(3*b^3) + ((b*B*d + A*b*e - 2*a*B*e)*(a + b*x)^4)/(4*b^3) + (B*e*(a + b*
x)^5)/(5*b^3)

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Rubi [A]  time = 0.0710218, antiderivative size = 75, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 1, integrand size = 18, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.056, Rules used = {77} \[ \frac{(a+b x)^4 (-2 a B e+A b e+b B d)}{4 b^3}+\frac{(a+b x)^3 (A b-a B) (b d-a e)}{3 b^3}+\frac{B e (a+b x)^5}{5 b^3} \]

Antiderivative was successfully verified.

[In]

Int[(a + b*x)^2*(A + B*x)*(d + e*x),x]

[Out]

((A*b - a*B)*(b*d - a*e)*(a + b*x)^3)/(3*b^3) + ((b*B*d + A*b*e - 2*a*B*e)*(a + b*x)^4)/(4*b^3) + (B*e*(a + b*
x)^5)/(5*b^3)

Rule 77

Int[((a_.) + (b_.)*(x_))*((c_) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandIntegran
d[(a + b*x)*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, n}, x] && NeQ[b*c - a*d, 0] && ((ILtQ[
n, 0] && ILtQ[p, 0]) || EqQ[p, 1] || (IGtQ[p, 0] && ( !IntegerQ[n] || LeQ[9*p + 5*(n + 2), 0] || GeQ[n + p + 1
, 0] || (GeQ[n + p + 2, 0] && RationalQ[a, b, c, d, e, f]))))

Rubi steps

\begin{align*} \int (a+b x)^2 (A+B x) (d+e x) \, dx &=\int \left (\frac{(A b-a B) (b d-a e) (a+b x)^2}{b^2}+\frac{(b B d+A b e-2 a B e) (a+b x)^3}{b^2}+\frac{B e (a+b x)^4}{b^2}\right ) \, dx\\ &=\frac{(A b-a B) (b d-a e) (a+b x)^3}{3 b^3}+\frac{(b B d+A b e-2 a B e) (a+b x)^4}{4 b^3}+\frac{B e (a+b x)^5}{5 b^3}\\ \end{align*}

Mathematica [A]  time = 0.026663, size = 96, normalized size = 1.28 \[ \frac{1}{3} x^3 \left (a^2 B e+2 a A b e+2 a b B d+A b^2 d\right )+a^2 A d x+\frac{1}{4} b x^4 (2 a B e+A b e+b B d)+\frac{1}{2} a x^2 (a A e+a B d+2 A b d)+\frac{1}{5} b^2 B e x^5 \]

Antiderivative was successfully verified.

[In]

Integrate[(a + b*x)^2*(A + B*x)*(d + e*x),x]

[Out]

a^2*A*d*x + (a*(2*A*b*d + a*B*d + a*A*e)*x^2)/2 + ((A*b^2*d + 2*a*b*B*d + 2*a*A*b*e + a^2*B*e)*x^3)/3 + (b*(b*
B*d + A*b*e + 2*a*B*e)*x^4)/4 + (b^2*B*e*x^5)/5

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Maple [A]  time = 0., size = 101, normalized size = 1.4 \begin{align*}{\frac{{b}^{2}Be{x}^{5}}{5}}+{\frac{ \left ( \left ( A{b}^{2}+2\,Bba \right ) e+{b}^{2}Bd \right ){x}^{4}}{4}}+{\frac{ \left ( \left ( 2\,Aba+B{a}^{2} \right ) e+ \left ( A{b}^{2}+2\,Bba \right ) d \right ){x}^{3}}{3}}+{\frac{ \left ({a}^{2}Ae+ \left ( 2\,Aba+B{a}^{2} \right ) d \right ){x}^{2}}{2}}+{a}^{2}Adx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x+a)^2*(B*x+A)*(e*x+d),x)

[Out]

1/5*b^2*B*e*x^5+1/4*((A*b^2+2*B*a*b)*e+b^2*B*d)*x^4+1/3*((2*A*a*b+B*a^2)*e+(A*b^2+2*B*a*b)*d)*x^3+1/2*(a^2*A*e
+(2*A*a*b+B*a^2)*d)*x^2+a^2*A*d*x

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Maxima [A]  time = 1.03159, size = 135, normalized size = 1.8 \begin{align*} \frac{1}{5} \, B b^{2} e x^{5} + A a^{2} d x + \frac{1}{4} \,{\left (B b^{2} d +{\left (2 \, B a b + A b^{2}\right )} e\right )} x^{4} + \frac{1}{3} \,{\left ({\left (2 \, B a b + A b^{2}\right )} d +{\left (B a^{2} + 2 \, A a b\right )} e\right )} x^{3} + \frac{1}{2} \,{\left (A a^{2} e +{\left (B a^{2} + 2 \, A a b\right )} d\right )} x^{2} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^2*(B*x+A)*(e*x+d),x, algorithm="maxima")

[Out]

1/5*B*b^2*e*x^5 + A*a^2*d*x + 1/4*(B*b^2*d + (2*B*a*b + A*b^2)*e)*x^4 + 1/3*((2*B*a*b + A*b^2)*d + (B*a^2 + 2*
A*a*b)*e)*x^3 + 1/2*(A*a^2*e + (B*a^2 + 2*A*a*b)*d)*x^2

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Fricas [A]  time = 1.60556, size = 277, normalized size = 3.69 \begin{align*} \frac{1}{5} x^{5} e b^{2} B + \frac{1}{4} x^{4} d b^{2} B + \frac{1}{2} x^{4} e b a B + \frac{1}{4} x^{4} e b^{2} A + \frac{2}{3} x^{3} d b a B + \frac{1}{3} x^{3} e a^{2} B + \frac{1}{3} x^{3} d b^{2} A + \frac{2}{3} x^{3} e b a A + \frac{1}{2} x^{2} d a^{2} B + x^{2} d b a A + \frac{1}{2} x^{2} e a^{2} A + x d a^{2} A \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^2*(B*x+A)*(e*x+d),x, algorithm="fricas")

[Out]

1/5*x^5*e*b^2*B + 1/4*x^4*d*b^2*B + 1/2*x^4*e*b*a*B + 1/4*x^4*e*b^2*A + 2/3*x^3*d*b*a*B + 1/3*x^3*e*a^2*B + 1/
3*x^3*d*b^2*A + 2/3*x^3*e*b*a*A + 1/2*x^2*d*a^2*B + x^2*d*b*a*A + 1/2*x^2*e*a^2*A + x*d*a^2*A

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Sympy [A]  time = 0.102814, size = 116, normalized size = 1.55 \begin{align*} A a^{2} d x + \frac{B b^{2} e x^{5}}{5} + x^{4} \left (\frac{A b^{2} e}{4} + \frac{B a b e}{2} + \frac{B b^{2} d}{4}\right ) + x^{3} \left (\frac{2 A a b e}{3} + \frac{A b^{2} d}{3} + \frac{B a^{2} e}{3} + \frac{2 B a b d}{3}\right ) + x^{2} \left (\frac{A a^{2} e}{2} + A a b d + \frac{B a^{2} d}{2}\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)**2*(B*x+A)*(e*x+d),x)

[Out]

A*a**2*d*x + B*b**2*e*x**5/5 + x**4*(A*b**2*e/4 + B*a*b*e/2 + B*b**2*d/4) + x**3*(2*A*a*b*e/3 + A*b**2*d/3 + B
*a**2*e/3 + 2*B*a*b*d/3) + x**2*(A*a**2*e/2 + A*a*b*d + B*a**2*d/2)

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Giac [A]  time = 1.8317, size = 161, normalized size = 2.15 \begin{align*} \frac{1}{5} \, B b^{2} x^{5} e + \frac{1}{4} \, B b^{2} d x^{4} + \frac{1}{2} \, B a b x^{4} e + \frac{1}{4} \, A b^{2} x^{4} e + \frac{2}{3} \, B a b d x^{3} + \frac{1}{3} \, A b^{2} d x^{3} + \frac{1}{3} \, B a^{2} x^{3} e + \frac{2}{3} \, A a b x^{3} e + \frac{1}{2} \, B a^{2} d x^{2} + A a b d x^{2} + \frac{1}{2} \, A a^{2} x^{2} e + A a^{2} d x \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^2*(B*x+A)*(e*x+d),x, algorithm="giac")

[Out]

1/5*B*b^2*x^5*e + 1/4*B*b^2*d*x^4 + 1/2*B*a*b*x^4*e + 1/4*A*b^2*x^4*e + 2/3*B*a*b*d*x^3 + 1/3*A*b^2*d*x^3 + 1/
3*B*a^2*x^3*e + 2/3*A*a*b*x^3*e + 1/2*B*a^2*d*x^2 + A*a*b*d*x^2 + 1/2*A*a^2*x^2*e + A*a^2*d*x